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4. Non-Porous Immobilization (40 points): Two enzymes are both immobilized on the same flat, non-porous surface. For Enzyme A, the substrate is Ss. For Enzyme B, the substrate is $2. The product of the first reaction is S2: Si S2 6.0 R 4.5 or J * 106 3.0 mg cm 1.5 o 0 + - 0 20 40 60 80 100 120 S, [mg/L) Figure ! a. From Figure 1, the rate of the first surface reaction is shown as a function of surface concentrations of S. If the bulk concentration of S, is 120 mg/L and the mass transfer coefficient is 4 x 10-5 cm/s, what is the rate of consumption of S, for a 1 cm surface? What is the surface concentration of S.? Solve for this value analytically as given in class and with a graphical plot of the first reaction rate vs the diffusion of Si. b. Assume that the rate of the second surface reaction also follows the kinetics shown in Figure 1. If the bulk concentration of Sis 15 mg/L and the mass transfer coefficient is 4 x 10-5 cm/s what is the rate of consumption of S, for a 1 cm surface? What is the surface concentration of Sz? Solve for this value analytically as given in class and with a graphical plot of the second reaction rate vs the diffusion of S