please answer this with complete solution. i have provided a format please follow this. my other question already got answered like this and this is what i need for this problem as well. thank you. here's an example of what i need for my solution. please answer it until letter f.

Direction: On your answer sheets, match Column X to Column Y and Match Column Y to Column Z by writing the same and exact number or letter that corresponds to your answers for the following columns: Column X displays the Unknown Values, Column Y enumerates the Symbols of the Unknown Values, and Column Z reveals the exact answers. Consider the problem below for your reference. Problem: Random samples of size N = 2 are drawn from a finite population consisting of the number 5, 6, 7, 8, and 9. Compute for the Mean, Variance and Standard Deviation of the Population, and the Mean, Variance and Standard Deviation of the Sample Means. Column X Column Y Column Z A. Population _ 1. 0's a. 7 Mean B. Mean of the _2. OF b. 8.24 Sample Means C. Variance of the 3. He c. 7.11 Population D. Variance of the - 4. 0 d. 2.87 Sample Means E. Standard - 5. H e. 7 Deviation of the Population F. Standard _ 6. 02 f. 2.67 Deviation of the Sample Means 23Course Hero X + X -> C a coursehero.com/qa/wait/30769655/?question_id=30769655 6. the standard deviation of the samples means " is smaller than the standard deviation of the population Explanation: Solution: 1. Mean of the population= 5 1.47+1.58+1.67+1.69+1.51 _ 1.584 2. The mean of the sampling distribution of size 2: We need to get the combination of 5 (total number of possible students) taken 2 at the time using this formula: = n! r!(n-r)! where n=5, and r=2 5 ! 5*4*3*2*1 = 2!(5 2)! 2*1 (3*2*1) = 10 Therefore, there are 10 possible samples. Just take all the possible sample in size 2 of the following given: 1.47 1.58 1.67 1.69 1.51 combination (Column 1) mean (Column 2) 1.47 and 1.58 1.525 1.47 and 1.67 1.57 1.47 and 1.69 1.58 1.47 and 1.51 1.49 1.58 and 1.67 1.625 Thank you for your feedback Ask a new question We're glad that it was helpful! Keep your study momentum going W P O G 7:03 pm D ') ENG 03/05/2021 27Course Hero X + X -> C a coursehero.com/qa/wait/30769655/?question_id=30769655 1.51 combination (Column 1) mean (Column 2) 1.47 and 1.58 1.525 1.47 and 1.67 1.57 1.47 and 1.69 1.58 1.47 and 1.51 1.49 1.58 and 1.67 1.625 1.58 and 1.69 1.635 1.58 and 1.51 1.545 1.67 and 1.69 1.68 1.67 and 1.51 1.59 1.69 and 1.51 1.6 Get the average of the column 2 1.525+1.57+1.58+1.49+1.625+1.635+1.545-+1.68+1.59+1.6 - 1.584 10 The mean of the sampling distribution is 1.584 3. THE MEAN OF THE POPULATION IS ALWAYS EQUAL TO THE MEAN OD THE SAMPLE MEANS. 4. (a) Variance of the Population Solve this one using the formula: Thank you for your feedback Ask a new question We're glad that it was helpful! Keep your study momentum going O 7:03 pm D ') ENG 03/05/2021 27u Course Hero x + (- 9 C i courseheroLomlqa/wait/30769655/?que5tion_id:30769655 1.58 and 1.51 1.545 1.67 and 1.69 1.68 1.67 and 1.51 1.59 1.69 and 1.51 1.6 Get the average of the column 2 1.525+1.57+1.58+1.49+1.625+1.635+1.545+l.65+1.59+1.6 1 584 10 ' The mean of the sampling distribution is 1.584 3. THE MEAN OF THE POPULATION IS ALWAYS EQUAL TO THE MEAN OD THE SAMPLE MEANS. 2 4. (a) Variance of the Population '7 Solve this one using the formula; 2(Iimeany : N Column 1 Column 2 Column 5 Height (X) x7 mean (x7 mean)"2 1.47 70.114 0.012996 1.58 70.004 0.000016 1.67 0.086 0.007396 1.69 0.106 0.011236 1.51 70.074 0.005476 Thank you for your feedback We're glad that it was helpful! Keep your study momentum going a Wlulllll I It! in nu given uauaL anoiIUIIOOGIIGEi a new question _ 7:03 pm A [H a\") ENG 03/05/2021 ab