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Polymer Engineering Find the transition temperature of the glass with the specified volume having the equation VS) (L) = 1.137 + 1.4 X 10^-4 T
Polymer Engineering Find the transition temperature of the glass with the specified volume having the equation VS) (L) = 1.137 + 1.4 X 10^-4 T (at low temperature) - V(s) (H) = 1.145 +8.0 X 10-^-4 T(at high temperature) (a) liquid a login(T)] (b) supercooled liquid supercooled liquid V, S, H , Clogn glass a, glass crystal K2). (1). C (T), a(T) T 9 T m g T. Temperature, T Temperature, T V (a) Typical temperature dependence of the specific volume (v), entropy (S), or enthalpy (H) of glasses and crystals. Path (1) is not possible in, for example, atactic polymers lacking a crystalline ordering state. (b) Temperature dependence of the isobaric expansivity (also called coefficient of thermal expansion) [a= V-100 VIOT)P], heat capacity [ C p = (DHZOT)P], and log 10 of viscosity (n ), in the region of Tg
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