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Pranav is considering the improper integral for f(= ) de . where f : [190, oo) -> IR is the function defined by 17 arctan(x)

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Pranav is considering the improper integral for f(= ) de . where f : [190, oo) -> IR is the function defined by 17 arctan(x) + 4x tanh(x) + d f(x) = 73 (24 + 1023 - 7612 - 371 + 69) 102 for some positive real constant d. To decide whether this integral converges or diverges, Pranav intends to use the limit form of the comparison test. Help Pranav complete their argument: First, Pranav should find some simpler function g : [190, oo) -> IR such that lim f(I) Click for List T-+00 g(:) To this end, explain to Pranav why arctan(I) lim + a tanh(x) ) =Q T-+00 for any constant o. Essay box advice: In your explanation, you don't need to use exact Maple syntax or use the equation editor, as long as your expressions are sufficiently clear for the reader. For example, you can write arctan(I) lim + a tanh(x) ) as 'lim_(x->infinity) [ arctan(x)/x + alpha tanh(x) ], C-+00 [190, oo) as "[190, infinity)". A -A-IX BIUSXX Styles Font Size Words:0Then, we can choose, for example, the function defined by the rule g(z) = where p and q are constants with the values (entering a value for p as a fraction [not a decimal], if necessary, and choose q from the drop-down list.) D = M and q = Click for List Since Click for List Click for List Click for List the improper integral g(x)dr J190 Click for List and so we conclude by the Click for List that the improper integral f(x)dr Click for List Having found a method of solving the above problem, Pranav is now wondering whether any other constant p could have been used in the above procedure. Choose one of the following options: O p is not unique but p > 4. O The choice of p is unique. O p can be any positive real number

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