Question: Prove that NPNP coNP = NP . Be sure you understand what this means. A language is in NPNP coNP if it can
Prove that NPNPcoNP NP Be sure you understand what this means. A language is in NPNPcoNP if it can
be written in the form f j : g where is a polytime oracle TM and is a language
in NP coNP. In other words, has both an NPstyle algorithm and a coNPstyle one. More formally,
there are polytime TMs and such that f j : g f j : g
Hint: compare the situation to NPNP or NPcoNP, both of which are equal to Sigma Think about where the
additional quantier comes from in these cases, and why you might not need one in our problem
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