Question
Question 12(3 points) By the binomial series formula, we find1 1+x =(1+x) 1/2 =11 2 x+3 8 x 2 ... {version:1.1,math:(frac{1}{sqrt{1+x}=(1+x)^{-1/2}=1-frac{1}{2}x+frac{3}{8}x^2-...)}. The Maclaurin series of
Question 12(3 points)
By the binomial series formula, we find1
1+x
=(1+x)
1/2
=11
2
x+3
8
x
2
...
{"version":"1.1","math":"\(\frac{1}{\sqrt{1+x}=(1+x)^{-1/2}=1-\frac{1}{2}x+\frac{3}{8}x^2-...\)"}.
The Maclaurin series of the functionf(x) =ln(x+4+x
2
)
{"version":"1.1","math":"\(\ln{(x+\sqrt{4+x^2})}\)"}can be found by this binomial series and the fact thatd
dx
ln(x+4+x
2
)=1
4+x
2
{"version":"1.1","math":"\(\frac{d}{dx}\ln{(x+\sqrt{4+x^2})}=\frac{1}{\sqrt{4+x^2}\)"}.Let the Maclaurin series beln(x+4+x
2
)=
n=0
c
n
x
n
{"version":"1.1","math":"\(\ln{(x+\sqrt{4+x^2})}=\sum_{n=0}^\infty c_nx^n\)"}.Thenc
5
{"version":"1.1","math":""}=
Question 12 options:
a)
3
8
{"version":"1.1","math":"\(\frac{3}{8}\)"}
b)
3
1280
{"version":"1.1","math":"\(\frac{3}{1280}\)"}
c)
3
1280
{"version":"1.1","math":"\(-\frac{3}{1280}\)"}
d)
1
48
{"version":"1.1","math":"\(-\frac{1}{48}\)"}
e)
1
3240
{"version":"1.1","math":"\(\frac{1}{3240}\)"}
f)
1
48
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