Referring to attached, construct a 95% confidence interval estimate of the difference in proportion between the Kohler and Russell disks that are defective.

The provided answer is 0.02 to 0.16. Pls show the caculation.

TABLE 10-13 A quality control engineer is in charge of the manufacture of computer disks. Two different processes can be used to manufacture the disks. He suspects that the Kohler method produces a greater proportion of defects than the Russell method. He samples 150 of the Kohler and 200 of the Russell disks and nds that 27 and 18 of them, respectively, are defective. If Kohler is designated as \"Group 1" and Russell is designated as \"Group 2,\" perform the appropriate test at a level of signicance of 0.01