Question
Returning multiple values: tupling up the results def rank3(x,y,z, ascending-True): Given three integers, return them in order in a tuple of length three. An optional
Returning multiple values: tupling up the results def rank3(x,y,z, ascending-True): Given three integers, return them in order in a tuple of length three. An optional fourth argument (ascending) states whether output should be sorted ascending (argument is True) or descending (argument is False) o Examples: rank3(5, 3, 4) 4, rank3(6, 8, 6) -rank3(5, 3, False) (5,4,3) Allowing defaults, modifying a list in-place: def remove(val, xs, limit-None) : Remove multiple copies of val from xs (directly modify the list value that xs refers to). You may only remove up to the first limit occurrences of val. If limits=3, and xs had ten copies of val in it, then you'd only remove the first three and leave the last seven in place. When limit-None, there's truly no limit (and we remove all occurrences of val). Return None, because the work happened in-place. Negative or zero limit: no removals. hint: if you need to traverse a list from front to back, but you don't always want to go to the next index location, while loops can be very useful - we don't have to step forward each iteration. o o Note - some test cases are multiple lines (which we've avoided so far). You might need to notice the line number of a failed test, and go look at the code of that particular testing function, to see what's being attempted. This is a good habit to get into for projects. o Examples: >>> xs = [1,2,1,3,1,4,1,5,1] >>>remove (1,xs) [2, 3, 4, 5] >>>remove (1,xs, 3) >>> XS
>> xs = [1,2,1,3,1,4,1,5,1] >>>remove (1,xs) [2, 3, 4, 5] >>>remove (1,xs, 3) >>> XS\" v:shapes=\"Picture_x0020_549\">
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