Solve it as soon as possbile

$($a$)$ What is the current $($in $A)$ in each resistor?

$I_1=A$

$I_2=A$

$I_3=A$

$($b$)$ What is the power $($in W $)$ delivered to each resistor?

$P_1=$

$P_2=$

$P_3=,w$

$w$

$($c$)$ What is the total power $($in W $)$ supplied by both batteries?

$$

$($d$)$ What is the relationship between the total power supplied by the batteries and the power delivered to each resistor?

The total power supplied by the batteries is less than the sum of the power delivered to each resistor.

The total power supplied by the batteries is equal to the sum of the power delivered to each resistor.

$q,$ The total power supplied by the batteries is greater than the sum of the power delivered to each resistor.