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Suppose that you are told that the Fourier coefficients of a periodic function f(t) are given by F(n) == 1 4 (-1)+1-1 2 2
Suppose that you are told that the Fourier coefficients of a periodic function f(t) are given by F(n) == 1 4 (-1)"+1-1 2 2 n =0 otherwise (a) Use the Fourier series expansion formula (the Fourier sum) to plot the function f(t) over two periods, given that the period is T= 1 seconds. That means: use the Fourier series sum with the given coefficients and fundamental frequency. Cut off your Fourier expansion sum at some 'reasonable' number (n = 25 should work well for this problem) so that Maple can actually compute the finite sum. Plot the function (your cut-off Fourier series sum) for t=0..2 (2) since the given period is 1/2. (b) Repeat part (a) but now using a period of T=2 seconds (this means you use the same cut-off Fourier series sum, the same Fourier coefficients as part (a) but now your fundamental frequency is different). (c) What is the difference between part (a) and (b)
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