Suppose there is a linear chain of 2 links each with the same propagation delay d between a server and a client with a router in the middle between the two. Assume the transmission rate for the two links are Rs and Rc bps respectively. Suppose the server sends a pair of packets each of size L bits back-to-back to the client, and there is no other traffic on this path.

(1) If Rs<Rc, what is the packet inter-arrival time at the client? That is, how much time elapses from when the last bit of the first packet arrives at the client until the last bit of the second packet arrives at the client?

(2) Now assume that Rc = Rs/4 and the server starts to send the second packet T seconds after finishing sending the first packet. How large (in terms of L and Rs) must T be to ensure that second packet does not queue at the input queue of the router?

**Please provide a detailed explanation with the solution for the best understanding and REUSED ANSWERS WILL BE DOWNVOTED**