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t stat for a = -3.46 t stat for b1 = 2.50 t stat for b2 = 2.56 t stat for b3 = 0.29 t
t stat for a = -3.46 t stat for b1 = 2.50 t stat for b2 = 2.56 t stat for b3 = 0.29 t stat for b4 = 2.80 The bigger this value, the stronger the evidence to reject null hypothesis (no relationship between the two variables). For example, it shows that b1 has a strong value to reject the null hypothesis
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Finite Mathematics and Its Applications
Authors: Larry J. Goldstein, David I. Schneider, Martha J. Siegel, Steven Hair
12th edition
978-0134768588, 9780134437767, 134768582, 134437764, 978-0134768632
