The dissociation of calcium carbonate has an equilibrium constant of Kp=1.16 at 800.C. CaCO3(s)CaO(s)+CO2(g) (a) What is Kc for the reaction? Kc=0.0132 Correct Recall that Kb and Kc are related by the equation: Kp=Ke(RT)an The equation: CaCO3(s)CaO(s)+CO2(g) has n=1. Note that n=( gaseous products gaseous renctants). Applying the relationship: 1.16=Kt(0.082057Latm/Kmol(0.0820571073)11.16=Kt=0.0132 If you place 24.6g of CaCO3 in a 9.33L container at 800C, what is the pressure of CO2 in the container? Pressure = atm