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The following method was known to the ancient Greeks for computing square roots. Given a value x > 0, and a guess g for the

The following method was known to the ancient Greeks for computing square roots. Given a value x > 0, and a guess g for the square root, a better guess is (g + x/g)/2. Write a recursive helper method public static squareRootGuess(double x, double g). If g2 is approximately equal to x (that is, less than .0001 difference between x and g), return g, otherwise, return squareRootGuess with the better guess. Then write a method public static squareRoot(double x) that uses the helper method.

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Enter a number: 27

The square root is of 27.000 is 5.19615

Expected value: 5.19615

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