The reaction formula representing the ethanol (C2H6O) fermentation of Glucose (C6H12O6) is as follows.

C6H12O6 2C2H6O + 2CO2

It is known that 50% of the glucose injected is used for cell growth and maintenance, and only the remaining 50% is converted to ethanol. Under these conditions, how much glucose must be put into the fermentation tank to produce 1.0 x 103g of ethanol? (Glucose's molecular weight = 180, Ethanol's molecular weight = 46, two significant figures)

Please give me an exact answer