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this is the given code Source.asmx Source.asm 1 . 386 2 .model flat, stdcall 3 .stack 4096 4 5 ExitProcess PROTO, dwExitCode:DWORD 6 7 8
this is the given code
Source.asmx Source.asm 1 . 386 2 .model flat, stdcall 3 .stack 4096 4 5 ExitProcess PROTO, dwExitCode:DWORD 6 7 8 .code 9 main PROC 10 mov eax, 12345678h 11 mov ax, 1122h 12 mov bl, al 13 mov bl, ah 14 mov al, 89h 15 add al, 10h 16 sub al, al 17 mov al, 98h 18 add al, 89h 19 20 21 invoke ExitProcess, O 22 main ENDP 23 END main Debug through each line of code and explain the register content and flags. (We already answered line 10 to 13 for your reference. Start writing your answer from Line 14) Line: 10 Instruction:mov eax, 12345678h Register value: EAX = 12345678 Explanation: 12345678 is a hexadecimal value which is 32-bit in binary. EAX register is also 32- bit. Line 11: Instruction: mov ax, 1122h Register value: EAX = 12341122h Explanation: 1122 is hexadecimal and it is 16-bit in binary. this mov instruction only updates AX (16 bit) register, a part of EAX register. That's why you can see that the upper portion of EAX register is NOT updated. 22 Line 12: Instruction:mov bl, al Register value: EBX = ____ Explanation: AL register is 8-bit long. When you mov the content of al register (22) to BL register, it only updates the first 8-bit of the EBX register. The rest contains the garbage value. Line 13 Instruction:mov bl, ah Register value: EBX = ---- 11 Explanation: Ah register is 8-bit long. When you mov the content of AH register (11) to BL register, it only updates the first 8-bit of the EBX register. The rest contains the garbage value. Line 14: Instruction: mov al, 89h What Register value of EAX register, after executing line 14. Explain the content of the EAX register. Line 15 Instruction: add al, 10h What Register value of EAX, after executing line 15? Do you see any change in flags? Show the step of the hexadecimal addition. Line 16 Instruction: sub al, al What Register value of EAX, after executing line 16? Do you see any change in flags? Show the step of the hexadecimal subtraction. Line 17, 18: Instruction: mov al, 98h add al, 89h What Register value of EAX, after executing line 17 and 18? Do you see any change in flags? Show the step of the hexadecimal additionStep by Step Solution
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