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Use the substitution, t = tan Evaluate to find I se secx dx. 4x5 + 6x4 + 2x + 3x - 5x - 7

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Use the substitution, t = tan Evaluate to find I se secx dx. 4x5 + 6x4 + 2x + 3x - 5x - 7 S x3 + 2x + x dx.

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We know that secx 1cosx Using the halfangle identity for cosine we have cosx 1 2sin2x2 substitute t tanx2 into this expression cosx 1 2tan2x21 tan2x2 ... blur-text-image

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