An animal breeder can buy four types of food for Vietnamese pot-bellied pigs. Each case of Brand A contains 25 units of fiber, 30 units of protein, and 30 units of fat. Each case of Brand B contains 50 units of fiber, 30 units of protein, and 20 units of fat. Each case of Brand C contains 75 units of fiber, 30 units of protein, and 20 units of fat. Each case of Brand D contains 150 units of fiber, 90 units of protein, and 50 units of fat. How many cases of each brand should the breeder mix together to obtain a food that provides 1425 units of fiber, 720 units of protein. and 480 units of fat? Let x represent the number of cases of Brand A, y represent the number of cases of Brand B, z represent the number of cases of Brand C, and w represent be the number of cases of Brand D. There are four ways in which the breeder can mix brands to obtain a food that provides 1425 units of fiber, 720 units of protein, and 480 units of fat. If w=0, the solution is (...0). If w=1, the solution is ( .1). If w=2, the solution is ( 2). If w=3, the solution is 3). An animal breeder can buy four types of food for Vietnamese pot-bellied pigs. Each case of Brand A contains 25 units of fiber, 30 units of protein, and 30 units of fat. Each case of Brand B contains 50 units of fiber, 30 units of protein, and 20 units of fat. Each case of Brand C contains 75 units of fiber, 30 units of protein, and 20 units of fat. Each case of Brand D contains 150 units of fiber, 90 units of protein, and 50 units of fat. How many cases of each brand should the breeder mix together to obtain a food that provides 1425 units of fiber, 720 units of protein. and 480 units of fat? Let x represent the number of cases of Brand A, y represent the number of cases of Brand B, z represent the number of cases of Brand C, and w represent be the number of cases of Brand D. There are four ways in which the breeder can mix brands to obtain a food that provides 1425 units of fiber, 720 units of protein, and 480 units of fat. If w=0, the solution is (...0). If w=1, the solution is ( .1). If w=2, the solution is ( 2). If w=3, the solution is 3).