v(1/6) - v(0) 1/6 - 0 = At 2:00 p.m. a car's speedometer reads 30 mi/h. At 2:10 p.m. it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acceleration is exactly 120 mi/h. Let v(t) be the velocity of the car t hours after 2:00 p.m. Then By the Mean Value Theorem, there is a number c such that 0