Way up north in the frozen lands it's usually handy to transport gear and supplies via a sled. Suppose you are to transport 54 kg worth of supplies on a 10. kg sled. You then pull on the sled with a force of 580 N at an angle of 30. above the horizon. Assume a coefficient of friction to be 0.025 Draw a free body diagram of the sled with all forces labeled. (10 pts) the force that the floor gives = 9.81 5801 -7 30% m 54kg Giokg 9-9.8In P Not a force Determine the acceleration on the sled. (20 pts) 54 + 10 = 64kg a= f/m = f/m = Fx = ? {Fy=? 50xX/N1/64kg = 7.8m/62 -15 V= Vitat V = 0 + 7.8 m/s (305) = 23 mm velocity No it's not 580N COS (30) = 502 N Not a Velocity Normal force : Assuming the sled is at rest determine how far you would travel in 3.0 seconds (10 pts) Ax 2 -7