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We now collect n independent copies of X denoted X 1 , . . . , Xn and we apply one step of the EM
We now collect n independent copies of X denoted X Xn and we apply one step of the EM algorithim importante note: the Estep and the the Mstep will be different from the mixture of gaussian case and need to be recomputed using the specific form of the exponential PDF
The EM algorithm will always output an esimator lambdahat such that:
alphaXbar or equal to lambdahat or equal to Xbar
What is the smallest value of alpha?
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