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What is the motivation for designing IPv6? The depletion of IPv4 addresses New technology can bring new innovation New web technologies demand new IP addressing

What is the motivation for designing IPv6?

The depletion of IPv4 addresses
New technology can bring new innovation
New web technologies demand new IP addressing scheme
IPv4 technology cannot accommodate network heterogeneity

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Question 25 pts

Given the IP: 146.186.32.100 and Subnet Mask: 255.255.0.0, what is the network portion of this IP address?

146.186.32
146.186
100
146

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Question 35 pts

Given the IP: 192.168.32.100 and CIDR: /16, what is the host portion of this IP address?

100
32.100
192.168
192

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Question 45 pts

Given the IP: 192.168.32.100 and CIDR: /24, what is the host portion of this IP address?

100
168.32.100
192
192.168.32

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Question 55 pts

Given the IP: 146.186.32.100 and Subnet Mask: 255.255.0.0, what is the broadcast IP address in this network?

146.186.32.255
146.186.255.255
146.186.255.0
255.255.255.255

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Question 65 pts

Given the IP: 146.186.0.0/24, what is a valid host address in this network?

146.186.1.50
146.50.50.50
146.186.0.50
146.186.255.50.

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Question 75 pts

Given the IP: 192.168.32.100 and CIDR: /16, what is the network portion of this IP address?

192
32.100
192.168
100

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Question 85 pts

Which is a valid IPv6 address?

33FA:246E::AE0F::3829:245C
33FA:246E::AE0F:3829:245C
33FA:246E:0000::0000:AE0F:245C
33FA:246E:AE0F:3829:245C

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Question 95 pts

An IPv4 address is divided into parts: ______ and _______.

Network and host
Physical and logical
Global and local
Network and subnet mask

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Question 105 pts

Given the IP: 146.186.32.100 and Subnet Mask: 255.255.0.0, what is the host portion of this IP address?

146.186
32.100
146.186.32
100

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Question 115 pts

What is the loopback address?

192.168.0.1
127.0.0.1
192.168.255.255
255.255.255.255

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Question 125 pts

IPv4 addresses are ______ bit binary numbers.

32
128
16
64

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Question 135 pts

Destination Mask Next Hop
120.130.55.0 255.255.255.0 120.130.55.10
54.87.0.0 255.255.0.0 54.87.10.10
128.1.0.0 255.255.0.0 deliver directly
92.63.0.0 255.255.0.0 92.63.10.10
92.63.20.0 255.255.255.0 92.63.20.10

According to the forwarding table above, what should the router do when it receives 92.63.30.3?

Forward the datagram to 92.63.20.10
Forward the datagram to 92.63.10.10
Deliver the datagram to a host in the network
Forward the datagram to 120.130.55.10

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Question 145 pts

Destination Mask Next Hop
120.130.55.0 255.255.255.0 120.130.55.10
54.87.0.0 255.255.0.0 54.87.10.10
128.1.0.0 255.255.0.0 deliver directly
92.63.0.0 255.255.0.0 92.63.10.10
92.63.20.0 255.255.255.0 92.63.20.10

According to the forwarding table above, what should the router do when it receives 54.87.14.9?

Forward the datagram to 92.63.10.10
Deliver the datagram to a host in the network
Forward the datagram to 120.130.55.10
Forward the datagram to 54.87.10.10

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Question 155 pts

There are one entry per ______ in the datagram forwarding table.

Server
Router
Network
Host

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Question 165 pts

Destination Mask Next Hop
120.130.55.0 255.255.255.0 120.130.55.10
54.87.0.0 255.255.0.0 54.87.10.10
128.1.0.0 255.255.0.0 deliver directly
92.63.0.0 255.255.0.0 92.63.10.10
92.63.20.0 255.255.255.0 92.63.20.10

According to the forwarding table above, what should the router do when it receives 92.63.20.3?

Forward the datagram to 92.63.10.10
Deliver the datagram to a host in the network
Forward the datagram to 120.130.55.10
Forward the datagram to 92.63.20.10

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Question 175 pts

What does the router do when it receives a datagram that matches more than one entry in the forwarding table?

Forward the datagram to anyone entry that matches
Use longest prefix match and forward it to next hop
Remove all but one entry in the forwarding table and forward the datagram to next hop
Discard the datagram

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Question 185 pts

IP datagrams are _________________.

Different depends on the Network Interface Layer protocol
Different depends on the type of transmission media
The same format regardless the underlying network
Different depends on the type of network

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Question 195 pts

Host A sends a datagram to host B through network #1 (MTU = 1000 bytes), network #2 = (MTU = 1200 bytes), and network #3 (MTU = 1500 bytes). What is the path MTU from host A to host B?

1000 bytes
1200 bytes
3700 bytes
1500 bytes

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Question 205 pts

Host A sends a datagram (length = 2200 bytes) to host B through network #1 (MTU = 1000 bytes), network #2 = (MTU = 1200 bytes), and network #3 (MTU = 1500 bytes). How many fragment(s) will be delivered to host B assuming there is no loss or duplicate?

2
1
3
4

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