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Why is 5NF less practical than 3NF or 4NF in a real-world setting? It creates too much data redundancy. Each table contains more than one

Why is 5NF less practical than 3NF or 4NF in a real-world setting?


It creates too much data redundancy.


Each table contains more than one candidate key. 


It contains very little redundancy but sacrifices performance. 


It eliminates multivalued dependencies.

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