47. Let X be a normal random variable with mean and variance . Use the results...

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47. Let X be a normal random variable with mean µ and variance σ². Use the results of Theoretical Exercise 46 to show that E[X^n] = ∑ (n/2j) (µ^(n-2j)) (σ²(2j)) / 2j!

j=0

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In the equation above, [1/2] is the largest integer less than or equal to n/2.
Check your answer by letting 1 and n = 2.

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