The average income in Connecticut in 2013 was $60,000 per person per year. Suppose the standard deviation

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The average income in Connecticut in 2013 was $60,000 per person per year. Suppose the standard deviation is $30,000 and the distribution is right-skewed. Suppose we take a random sample of 400 residents of Connecticut. We want to find the probability that the sample mean will be more than $3000 away from the population mean. The TI-84 output is shown.
The average income in Connecticut in 2013 was $60,000 per

a. Why is the distribution Normal and not right-skewed like the population?
b. Why is the z-score 2?
c. What is the probability that the sample mean will be more than $3000 away from the population mean?

Distribution
The word "distribution" has several meanings in the financial world, most of them pertaining to the payment of assets from a fund, account, or individual security to an investor or beneficiary. Retirement account distributions are among the most...
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