The combustion of acetylene, C2H2, is a spontaneous reaction given by the equation 2C2H2(g) + 5O2(g)
Question:
2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l)
As expected for a combustion, the reaction is exothermic. What is the sign of ∆Ho? What do you expect for the sign of ∆So? Explain the spontaneity of the reaction in terms of the enthalpy and entropy changes.
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The sign of S should be negative because there is a decrease in moles of gas n ...View the full answer
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