The potential for a mass hanging from a spring is V (y) = ky2/2+mgy, where y =

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The potential for a mass hanging from a spring is V (y) = ky2/2+mgy, where y = 0 corresponds to the position of the spring when nothing is hanging from it. Find the frequency of small oscillations around the equilibrium point.

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Introductory Classical Mechanics

ISBN: 978-0521876223

1st edition

Authors: David Morin

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Question Posted: Jul 14, 2011 03:16 PM

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The potential for a mass hanging from a spring is V (y) = ky2/2+mgy, where y =

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Introductory Classical Mechanics

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