The rate law for the reaction of HO- with tert-butyl bromide to form an elimination product in
Question:
rate = 7.1 × 10-5[tert-butyl bromide][HO-] + 1.5 × 10-5[tert-butyl bromide]
What percentage of the reaction takes place by the E2 pathway when these conditions exist?
a. [HO-] = 5.0 M
b. [HO-] = 0.0025 M
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
a E2E2 E1 71 10 5 5071 10 5 50 15 10 5 355 10 5 355 50 15 105 ...View the full answer
Answered By
Jacob Festus
I am a professional Statistician and Project Research writer. I am looking forward to getting mostly statistical work including data management that is analysis, data entry using all the statistical software’s such as R Gui, R Studio, SPSS, STATA, and excel. I also have excellent knowledge of research and essay writing. I have previously worked in other Freelancing sites such as Uvocorp, Essay shark, Bluecorp and finally, decided to join the solution inn team to continue with my explicit work of helping dear clients and students achieve their Academic dreams. I deliver, quality and exceptional projects on time and capable of working under high pressure.
1263+ Reviews
2858+ Question Solved
Related Book For 
Question Posted:
