The vapour pressure of the ketone carvone (M 150 2 g mol 1), a component of oil of spearmint, is as follows What are (a) The normal boiling point and (b) The enthalpy of vaporization of carvone 0 C 57 4 100 4 133 0 157 3 203 5 227 5 P Torr 10 0 40 0 100 400 760 1 00...

a Follow the procedure in Problem 48 but note that T 2275C is obvious ...

The vapour pressure of the ketone carvone (M = 150.2 g mol-1), a component of oil of

Question:

The vapour pressure of the ketone carvone (M = 150.2 g mol-1), a component of oil of spearmint, is as follows:

0/’C 57.4 100.4 133.0 157.3 203.5 227.5 P/Torr 10.0 40.0 100 400 760 1.00

What are?

(a) The normal boiling point and

(b) The enthalpy of vaporization of carvone?

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Physical Chemistry

ISBN: 978-0716743880

7th Edition

Authors: Peter Atkins

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Question Posted: Jan 30, 2010 06:35 AM

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The vapour pressure of the ketone carvone (M = 150.2 g mol-1), a component of oil of

Question:

0/’C 57.4 100.4 133.0 157.3 203.5 227.5 P/Torr 10.0 40.0 100 400 760 1.00

Step by Step Answer:

a Follow the procedure in Problem 48 but note that T 2275C is obvious ...View the full answer

Physical Chemistry

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