Will a precipitate of Cd(OH)2 form if 1.0 mL of 1.0 M Cd(NO3)2 is added to 1.0
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Cd2+(aq) + 4NH3(aq) ⇌ Cd(NH3)42+(aq) K = 1.0 × 107
Cd(OH)2(s) ⇌ Cd2+(aq) + 2OH-(aq) Ksp = 5.9 × 10-15
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10 mL 10 mmol Cd 2 added to the ammonia solution Thus Cd 2 0 10 10 3 molL We will first calculate th...View the full answer
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