Refer to Example 7.1 and the problem of estimating m, the average length of stay of a hospital’s patients. The lengths of stay (in days) for the n = 100 sampled patients are shown in Table 7.1. Use the data to find a 95% confidence interval for m and interpret the result.

Table 7.1 Lengths of Stay (in Days) for 100 Patients 2 3 8 6 4 4 6 4 2 5 8 10 4 4 4 2 1 3 2 10 1 3 2 3 4 3 5 2 4 1 2 9 1 7 17 9 9 9 4 4 1 1 1 3 1 6 3 3 2 5 1 3 3 14 2 3 9 6 6 3 5 1 4 6 11 22 1 9 6 5 2 2 5 4 3 6 1 5 1 6 17 1 2 4 5 4 4 3 2 3 3 5 2 3 3 2 10 2 4 2