A satellite orbiting at a distance R from the center of the earth follows the circular path
Question:
A satellite orbiting at a distance R from the center of the earth follows the circular path x(t) = R cosωt, y(t) = R sinωt.
(a) Show that the period T (the time of one revolution) is T = 2π/ω.
(b) According to Newton’s Laws of Motion and Gravity,
where G is the universal gravitational constant and me is the mass of the earth. Prove that R3/T2 = Gme/4π2.
Thus, R3/T2 has the same value for all orbits (a special case of Kepler’s Third Law).
Transcribed Image Text:
x' (t) = -Gme X R³⁹ y"(t) = -Gme R³
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a As shown in Example 4 the circular path has constant speed of d...View the full answer
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