For the synthesis of ammonia at 500C, the equilibrium constant is 6.0 10 2 L 2 /mol

Question:

For the synthesis of ammonia at 500°C, the equilibrium constant is 6.0 ×10^–2 L²/mol². Predict the direction in which the system will shift to reach equilibrium in each of the following cases.

-3 a. [NH3]0= 1.0 10-3 M; [Nlo = 1.0 x 105 M; [Hlo = 2.0 10- M b. [NH3]0 = 2.00 x 10-4 M; [Nl0 = 1.50 x 105

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a First we calculate the value of Q NH30 N0H0 Q 10 x 103 molL 10 x 105 molL20 ...View the full answer

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Chemical Principles

ISBN: 9780618946907

6th Edition

Authors: Steven S Zumdahl

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Question Posted: Jan 23, 2024 12:01 PM

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For the synthesis of ammonia at 500C, the equilibrium constant is 6.0 10 2 L 2 /mol

Question:

-3 a. [NH3]0= 1.0 10-3 M; [Nlo 1.0 x 105 M; [Hlo = 2.0 10- M b. [NH3]0= 2.00 x 10-4 M; [Nlo 1.50 x 105 M; [Hlo = 3.54 x 10- M c. [NH3]0= 1.0 10 + M; [N]o = 5.0 M; [Hlo 1.0 x 10- M = =

Step by Step Answer:

a First we calculate the value of Q NH30 N0H0 Q 10 x 103 molL 10 x 105 molL20 ...View the full answer

Chemical Principles

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