Given the following data: calculate (Delta G^{circ}) for the reaction [6 mathrm{C}(s)+3 mathrm{H}_{2}(g) longrightarrow mathrm{C}_{6} mathrm{H}_{6}(l)] 2C6H6(l)

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Given the following data:

2C6H6(l) +150(g) 12CO(g) + 6HO(l) C(s) + O(g) H(g) + O2(g) - CO(g) HO(l) AG = -6399 kJ AG = -394 kJ AG =

calculate $\Delta G^{\circ}$ for the reaction

\[6 \mathrm{C}(s)+3 \mathrm{H}_{2}(g) \longrightarrow \mathrm{C}_{6} \mathrm{H}_{6}(l)\]

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Chemical Principles

ISBN: 9780618946907

6th Edition

Authors: Steven S Zumdahl

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Question Posted: Jan 25, 2024 05:02 AM

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Given the following data: calculate (Delta G^{circ}) for the reaction [6 mathrm{C}(s)+3 mathrm{H}_{2}(g) longrightarrow mathrm{C}_{6} mathrm{H}_{6}(l)] 2C6H6(l)

Question:

2C6H6(l) +150(g) 12CO(g) + 6HO(l) C(s) + O(g) H(g) + O2(g) - CO(g) HO(l) AG = -6399 kJ AG = -394 kJ AG = -237 kJ

Step by Step Answer:

To calculate the standard Gibbs free energy change Delta Gcirc for the target reaction 6 textCs 3 textH2g ightarrow textC6textH6l We need to use the s...View the full answer

Chemical Principles

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