The desorption (leaving of the surface) of a single molecular layer of n-butane from a single crystal
Question:
The desorption (leaving of the surface) of a single molecular layer of n-butane from a single crystal of aluminum oxide is found to be first order with a rate constant of 0.128/s at 150 K.
a. What is the half-life of the desorption reaction?
b. If the surface is initially completely covered with n-butane at 150 K, how long will it take for 25% of the molecules to desorb (leave the surface)? For 50% to desorb?
c. If the surface is initially completely covered, what fraction will remain covered after 10s? After 20s?
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: