CoCl 4 2- forms a tetrahedral complex ion and Co(CN) 6 3- forms an octahedral complex ion.
Question:
CoCl42- forms a tetrahedral complex ion and Co(CN)63- forms an octahedral complex ion. What is wrong about the following statements concerning each complex ion and the d orbital splitting diagrams?
a. CoCl42- is an example of a strong-field case having two unpaired electrons.
b. Because CN- is a weak-field ligand, Co(CN)63- will be a low-spin case having four unpaired electrons.
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Statement a is incorrect CoCl42 is an example of a weakfield case h...View the full answer
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Related Book For 
Chemistry An Atoms First Approach
ISBN: 9781305079243
2nd Edition
Authors: Steven S. Zumdahl, Susan A. Zumdahl
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