A 25.00-mL sample containing Fe3 [1] and Cu 2+ required 16.06 mL of 0.050 83 M EDTA
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A 25.00-mL sample containing Fe3[1] and Cu2+ required 16.06 mL of 0.050 83 M EDTA for complete titration. A 50.00-mL sample of the unknown was treated with NH4F to protect the Fe3+. Then Cu2+ was reduced and masked by thiourea. Addition of 25.00 mL of 0.050 83 M EDTA liberated Fe3+ from its fluoride complex to form an EDTA complex. The excess EDTA required 19.77 mL of 0.018 83 M Pb2+ to reach a xylenol orange end point. Find [Cu2+] in the unknown.
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Complexometry Metal cations denoted as M and EDTA denoted as Y form a complex ...View the full answer
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