Question: Potassium ion in a 250.0 (0.1) mL water sample was precipitated with sodium tetraphenylborate: The precipitate was filtered, washed, dissolved in an organic solvent, and
Potassium ion in a 250.0 (±0.1) mL water sample was precipitated with sodium tetraphenylborate:
![]()
The precipitate was filtered, washed, dissolved in an organic solvent, and treated with excess Hg(EDTA)2-:
![]()
The liberated EDTA was titrated with 28.73 (0.03) mL of 0.043 7(±0.000 1) M Zn2+. Find [K+] (and its absolute uncertainty) in the original sample.
K* + (C,H5)4B : KB(C,H5)4(s)
Step by Step Solution
3.42 Rating (152 Votes )
There are 3 Steps involved in it
The amount of EDTA liberated by potassium ions in the original sam... View full answer
Get step-by-step solutions from verified subject matter experts
