I do not know if I am doing correctly! The question is The shortest side of a triangle measures 7m. The lengths of the other 2 sides are consecutive integers - the hypotenuse being the longer of the two, find the lengths of the other two:

This is what I keep getting!

(x+2)^2=x^2+7^2

(x+2)(x+2)=x^2+49

x^2+4x+4=x^2+49

-x^2 -49 -x^2 -49

4x+53=0

-53 -53

4/4 -53/4 = -13.25