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Question: In the article by Gadd and Phipps (2012), they refer to the challenges faced by psychological and, specifically, neuropsychological assessment. Their study focused on

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In the article by Gadd and Phipps (2012), they refer to the challenges faced by psychological and, specifically, neuropsychological assessment. Their study focused on a preliminary standardisation of the Wisconsin Card Sorting Test (a non-verbal measure) for Setswana-speaking university students. The US normative sample is described as participants (N = 899) from both genders who were screened beforehand to exclude individuals with a history of neurological, learning, emotional and attention difficulties. The South African sample consisted of university students (N = 93) from both genders, between the ages of 18 and 29, who were screened in terms of hearing and visual impairments and any history of psychiatriceurological difficulties. The latter was done to prevent contamination of the results by these variables. The students were from the University of Limpopo, Medunsa Campus. Answer Questions 1 to 5.

Question 5

Gadd and Phipps (2012) found that the results of the South African sample on the Wisconsin Card Sorting Test did not resemble a normal distribution and could not be converted to a normal distribution. This implies that the ...

(1) mean performance of this sample cannot be calculated

(2) standard deviation will differ below and above the mean

(3) mean and standard deviation do not provide a predetermined distribution of performance

(4) results cannot be replicated

Would 1 be the correct answer?

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Lab Section Lab Partners) Gauss's Law Investigation #2: Charge Distributions on Conductors Introduction In Investigation #1, you discovered that the flux thru a closed surface (i.c., a Gaussian surface) is proportional to the charged enclosed by that surface: Flux thru Gaussian Surface & Charge enclosed by surface This relationship is known as Gauss's Law. In this investigation, you will use Gauss's Law to determine where charge is located on conducting objects of various shapes. Question 1 What is the electric field inside of the conducting material of any conductor? Question 2 Based on your answer to question 1, how many electric field lines are located inside of the conducting material of any conductor? The diagram at right shows a solid metal ball that bears an excess positive charge. When you studied electrostatics, you may have used reasoning about how charges attract and repel one another to determine where these charges lie on the metal ball. For now, however, it is important that you put this knowledge aside. The ultimate goal of this investigation is to help you learn how to apply Gauss's Law. Determining the locations of the excess charges on a conductor is just a bonus. Inside of the ball is a closed dotted path that represents a Gaussian surface. Remember that a Gaussian surface is a mathematical construct, not a real, physical object. Notice that the Gaussian surface is contained completely within the metallic material of the metal ball. Recall that the electric flux thru a closed surface is related to the number of field lines that pass thru that surface. Flux is positive if the field lines pass from inside to outside and is negative if the field lines pass from outside to inside. Question 3 What is the value of the electric flux thru the Gaussian surface shown in the diagram? Explain your reasoning.Question 1 8 points A. C. D. Each of the surfaces above has at least one of the following properties: I - represents z as a function of x only Il - represents a relation between x, y, and z, but none of the three variables is a function o the other two. Ill - represents z as a bivariate function of x and y IV - is quadratic in x and cubic in y V - is cubic in x and quadratic in y Determine which of the five properties is held by each surface.Consider the bivariate joint PDF of X and Y given by (c is some constant) fxy (u, v) = otherwise 1. Find the value of c. 2. Find p(X Sys 3. Find fy(v) the marginal distribution of Y. 4. Compute p(Y |Y = ) 9. Determine whether X and Y are independent

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