2. Suppose the following argument is made for threeegg quiches rather than four-egg quiches: Let x #
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2. Suppose the following argument is made for threeegg quiches rather than four-egg quiches: Let x # number of eggs that carry salmonella. Then p(0) 5 p(x 5 0) 5 (0.75)3 5 .422 for three-egg quiches and p(0) 5 p(x 5 0) 5 (0.75)4 5 .316 for four-egg quiches. What assumption must be made to justify these probability calculations? Do you think this is reasonable or not? Explain.
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Related Book For
Introduction To Statistics And Data Analysis
ISBN: 9781305445963
5th Edition
Authors: Roxy Peck, Chris Olsen, Jay L Devore
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