Question: In Figure a, a particle of elementary charge +e is initially at coordinate z = 20 nm on the dipole axis (here a z axis)
In Figure a, a particle of elementary charge +e is initially at coordinate z = 20 nm on the dipole axis (here a z axis) through an electric dipole, on the positive side of the dipole. (The origin of z is at the center of the dipole.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = –20 nm, on the negative side of the dipole axis. Figure b gives the work Wa done by the force moving the particle versus the angle θ that locates the particle relative to the positive direction of the z axis. The scale of the vertical axis is set by Was = 4.0 × 10–30 J. What is the magnitude of the dipole moment?
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(r 06-01) al
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From Eq 2430 and Eq 2414 we have for i 0 With r ... View full answer
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