Question: Does the following function for temperature satisfy the heat equation when there is no heat generation ( (alpha) is thermal diffusivity): [T=T_{0}+T_{m} exp left(frac{-2 pi^{2}

Does the following function for temperature satisfy the heat equation when there is no heat generation ( \(\alpha\) is thermal diffusivity):

\[T=T_{0}+T_{m} \exp \left(\frac{-2 \pi^{2} \alpha}{L^{2}} t\right) \sin \left(\frac{\pi x}{L}\right) \sin \left(\frac{\pi y}{L}\right)\]

You may assume \(L, T_{0}\), and \(T_{m}\) are also constant.

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

The hea... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related A Student S Guide Questions!