Question: Does the following function for temperature satisfy the heat equation when there is no heat generation ( (alpha) is thermal diffusivity): [T=T_{0}+T_{m} exp left(frac{-2 pi^{2}
Does the following function for temperature satisfy the heat equation when there is no heat generation ( \(\alpha\) is thermal diffusivity):
\[T=T_{0}+T_{m} \exp \left(\frac{-2 \pi^{2} \alpha}{L^{2}} t\right) \sin \left(\frac{\pi x}{L}\right) \sin \left(\frac{\pi y}{L}\right)\]
You may assume \(L, T_{0}\), and \(T_{m}\) are also constant.
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