This question concerns the reaction of copper(ii) carbonate with dilute hydrochloric acid. The equation for the reaction
Question:
This question concerns the reaction of copper(ii) carbonate with dilute hydrochloric acid. The equation for the reaction is:
CuCO3(s) + 2HCl(aq) → CuCl2(aq) + CO2(aq) + H2O(l)
a. Sketch a graph to show the rate of production of carbon dioxide when an excess of dilute hydrochloric acid is added. The reaction lasts 40 s and produces 60 cm3 of gas.
b. Find on your graph the part which shows:
(i) Where the reaction is at its fastest
(ii) When the reaction has stopped.
c. Calculate the mass of copper(ii) carbonate used to produce 60 cm3 of carbon dioxide. (Ar: C = 12; O = 16; Cu = 63.5. One mole of a gas occupies 24 dm3 at room temperature and pressure (rtp).)
d. Sketch a further graph using the same axes to show what happens to the rate at which the gas is produced if:
(i) The concentration of the acid is decreased
(ii) The temperature is increased.
Step by Step Answer:
The graph would show the rate of production of carbon dioxide on the yaxis and time on the xaxis The ...View the full answer
