Use the data in Appendix 2B and the fact that, for the half-reaction F₂(g) + 2 H⁺(aq) + 2 e^– → 2 HF(aq), E° = 13.03 V, to calculate the value of K_a for HF.

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2B STANDARD POTENTIALS AT 25 °C Potentials in Electrochemical Order Reduction half-reaction Strongly oxidizing H4XeO6+ 2 H+2 e → XeO3 + 3 H₂O F₂2 e 2 F- O3 + 2 H+ 2 e→O₂ + H₂O S₂O8² +2e →2 SO4²- Ag²+ +e → Agt Co³+ + e Co²+ H₂O2 + 2 H Au + e→→ Pb+ + 2 e + 2e →2 H₂O Au Pb²+ 2 HClO + 2 H+2 e → Cl₂ + 2 H₂O Cee Ce³+ →Mn²+ + 4H₂O 2 HBrO + 2 H+2 e Br2 + 2 H₂O MnO4 + 8 H+ + 5 e Mn³+ + e→ Mn²+ Au³+ + 3 e → Au Cl₂ + 2 e 2 CI Cr₂O7²- + 14 H+ + 6 e 2 Cr³+ + 7 H₂O O3+ H₂O + 2e →O₂ + 2 OH → 2H₂O O₂ + 4H+ + 4e Eº/V +3.0 +2.87 +2.07 +2.05 +1.98 +1.81 +1.78 +1.69 +1.67 +1.63 +1.61 +1.60 +1.51 +1.51 +1.40 +1.36 +1.33 +1.24 +1.23 Reduction half-reaction NO3 + H₂O + 2e →NO₂+ 2 OH Ti + e Ti³+ 2H+ +2 e Fe³+ + 3 e → H₂ Fe O₂ + H₂O + 2e → HO₂ + OH Pb²+ + 2 e pb In e In Sn²+ + 2 e AgI+ e → Sn Ag + I → Ni Ni²+ + 2e V³+ + e → V²+ Co²+ + 2e In³+ + 3 e Tl +e →→ Tl → Co In PbSO4 + 2 e Pb + SO4²- Ti³+ + e Ti²+ In²++eIn+ Cd²+ + 2 e Cd Cr³+ + eCr²+ Fe²+ + 2 e Fe Eº/V +0.01 0.00 0, by definition -0.04 -0.08 -0.13 -0.14 -0.14 -0.15 -0.23 -0.26 -0.28 -0.34 -0.34 -0.36 -0.37 -0.40 -0.40 -0.41 -0.44