In the discussion of the Lindemann mechanism, it was assumed that the rate of activation by collision with another reactant molecule, A, was the same as collision with a nonreactant molecule, M, such as a buffer gas. What if the rates of activation for these two processes are different? In this case, the mechanism becomes

a. Demonstrate that the rate law expression for this mechanism is

b. Does this rate law reduce to the expected form when [M] = 0?

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A* + M A + M A* + A + A= A* + A k2 →P A* k;(k[A][M] + k,[A]) K[AJ) k1[M] + k_q[A] + k_3 R =